As in Ref. [27], we diagonalize the s.p. Routhian,
For systems obeying the time-reversal symmetry,
vanishes [17] and the rotation in isospace is described by
a two-dimensional isocranking, that is,
In the absence of the Coulomb interaction, choosing
MeV,
MeV, and varying
from
to
, generates all the
and
IASs.
The angles
,
, and
correspond to the
HF solutions for
Ni (
),
Y (
in the odd-odd system), and
Sn (
),
respectively. Our example involves very exotic nuclei, including those
beyond the proton dripline. We find this case interesting because the nuclei at both ends of the isobaric chain are heavy and doubly magic, thus spherical.
As discussed in Ref. [27], with the Coulomb term off, the value of
is roughly equal to the absolute value of
difference between the proton and neutron Fermi energies in
Ni
or
Sn,
MeV. Then, the
isocranking term makes the Fermi energies of neutrons and protons
almost equal. In the presence of the Coulomb interaction, however, a large asymmetry between
develops between
Ni
(12.31MeV) and
Sn (33.62MeV).
Therefore, to
offset the difference of Fermi energies at
and
with Coulomb interaction present,
we set the values:
Using these expressions,
MeV and
MeV.
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Figure 1 shows that in the absence of
the Coulomb interaction, the total energy is independent of
. This should be the case, as the pnEDF is isospin-invariant
and thus the energy must be independent of the direction of the isospin vector.
This also turned out to be an important test on the derived
expressions and numerical code, as different terms of
pnEDF become active for different values of
. For
and
, solutions are unmixed and the
densities are block-diagonal in neutron and proton subspaces. At
intermediate values of
, the solutions are p-n mixed. For the
special case of
, proton and neutron densities are equally mixed.
When the Coulomb interaction is turned on, the total energy increases
with
(Fig. 1), because more and more
protons replace neutrons and the Coulomb repulsion grows.
The degree of p-n mixing can be
directly inferred from the expectation values of
plotted in Fig. 2(a). As expected, the p-n mixing
increases with
and reaches its maximum value for
, and then drops again. In
Fig. 2(b), we show
and it is seen
that the values of
,
, and
do correspond to
Ni,
Y, and
Sn,
respectively. The behavior of
and
weakly depends on whether the Coulomb term
is included or not. This is entirely due to our
choice of the shifted semicircle (18), whereupon the
linear constraint
absorbs the major
part of the isovector component of the Coulomb interaction.
The Coulomb interaction breaks isospin and thus induces
the isospin mixing in the HF wave function. To illustrate this,
Fig. 3 shows the average value of
for the converged HF solutions. For
the considered case of the
systems,
should be exactly equal to
in the absence of
isospin mixing.
However, as shown in Fig. 3, even in the absence
of the Coulomb interaction,
slightly deviates from this value. At the origin of this effect is the spurious isospin mixing [35,36,37]. Indeed, within the mean-field
approximation, the isospin symmetry is broken spontaneously as the HF wave function is not an isospin eigenstate. However, since the Skyrme EDF is isospin covariant [38,15], the HF solutions corresponding to different orientations in the isospin space are
degenerate in energy. While the neutron-proton mixing changes with the angle
,
must remain the same in the absence of the Coulomb interaction.
In the presence of the
Coulomb term, the isospin mixing is very
small in the isospin-stretched
configurations (for
and
) and reaches its maximum around
for
[37,39].
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The s.p. Routhians as functions of are shown in
Figs. 4 (without Coulomb) and 5 (with Coulomb). Eleven
spherical neutron levels and seven proton levels are occupied at
, and the neutron and proton Fermi energies are
shifted in such a way that the gaps in the s.p. spectra appear at
around
MeV (Fig. 4) and
MeV
(Fig. 5). Our choice of
guarantees that,
in the presence of the Coulomb interaction,
the s.p. Routhians near the Fermi surface do not cross as functions of
; this would have caused a
drastic structural changes of the mean-field and made
the adiabatic
tracing of the
IAS as a function of
extremely difficult.
At
and
, the s.p. states
have pure values of
. At
, most of the s.p. Routhians have
close to
zero, that is, they are fully p-n mixed.
![]() |
Figure 6 displays s.p. HF energies,
that is, s.p. Routhians with the isocranking term removed.
Note that these are not eigenvalues but the average values of the HF Hamiltonian,
calculated for states that are eigenstates of the Routhian (16).
With increasing , owing to the increasing Coulomb field,
s.p. states that increase proton (neutron) component gradually
increase (decrease) in energy.
![]() |
To better visualize the relative shifts of s.p. levels with , in Fig. 7 we show s.p.
energies relative to the energy of the 1
shell.
The figure nicely illustrates the effect of the Coulomb interaction
on the proton components of the s.p. orbits: the
relative level shifts correlate with their binding energies and
values [40,41]. Indeed, the
deeply (loosely) bound levels, which have smaller (larger) rms radii
and thus experience stronger (weaker) Coulomb repulsion, are shifted
up (down) in energy relative to the high-
1
shell.
Some of the calculated ,
IASs are predicted to appear beyond the proton
drip line. As seen in Fig. 6, energy
of the 1g
level (which is neutron at
and
proton at
) becomes positive at around
, where
.
At
, energies of the 1
, 1
,
2
, and 2
shells are positive. However, all these states are well localized by the Coulomb barrier, and thus
correspond to narrow resonances, whose energies can be reasonably well
described within the HO basis expansion [41].
![]() |
![]() |
To investigate properties of the unbound proton orbits, for the ground states of
,
nuclei, we performed the HFBRAD
[43] calculations (without p-n mixing). In
Fig. 10, we
show results obtained for the 1
and 2
proton
states. For each
isobar, a dot is placed at the
values of s.p. energies and radii, and lines show standard total
effective HF proton potentials.
The total
effective HF proton potential consists of the standard central, spin-orbit, centrifugal,
and Coulomb terms.
The proton 1
orbit in
Zr is bound, and in
Mo it becomes slightly unbound. This
result is consistent with the experimental observation, whereby the
last bound nucleus of the
isobaric chain, which is
experimentally known, is
Zr
. The rms radii of the
proton 1
orbits are about 5fm, and the s.p. wave
functions are still localized, even if the orbits become unbound.
This is because the 1
and 2
protons
occupy states well below the potential barrier, which pushes the proton continuum up in energy, thus effectively extending the range of nuclear landscape into the proton-unstable region [44,21,22].
It is worth noting that the 2 orbit,
which has a small centrifugal barrier, is bound up to around (
) in Fig. 6. This is consistent
with Fig. 10 that shows that the s.p. energy of 2
is unbound in
Ru
.
In the presence of p-n mixing,
the proton components of the s.p. states are smaller than those in
the pure proton states, and this effectively reduces the repulsive
Coulomb energies of the 1
orbits.
Jacek Dobaczewski 2014-12-07