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Previous: The isoscalar 1 mode
The isovector 0
and isoscalar, isovector 2
modes
Figure 6
displays strength functions for the
0
and 2
channels in
Sn and
Sn. (We discussed the
isoscalar
mode above to illustrate the accuracy of our solutions, but
include it here as well for completeness.)
Figure 6:
Isoscalar and isovector strength functions
for (a) the 0
channel of
Sn, (b) the 0
channel of
Sn,
(c) the 2
channel of
Sn, and (d) the 2
channel of
Sn.
The cutoff
is 150 MeV and
is
.
![\includegraphics[width=14cm]{Sn120174}](img98.png) |
The calculations show the appearance of low-energy
strength -- both isovector and isoscalar -- and low-energy isovector
2
strength in
Sn, though in none of these instances is the
phenomenon quite as dramatic as in the isoscalar
channel.
The EWSR for the isoscalar 2
transition operator,
 |
(8) |
can be written as [75]
 |
(9) |
The sum rule is obeyed as well in the 2
isoscalar channel as in the
and
channels, the
only difference being that one needs to include quasiparticle states with
for
Sn.
For
Sn (
Sn) from Fig. 6, the EWSR is 37222 (34971)
MeVfm
while the QRPA value is 37030 (35010)
MeVfm
.
While on the topic of the sum rule, we
display
in Table 2 the
-dependence of
the EWSR
for several channels in
Sn, with
fm.
By taking
we appear to obtain essentially
the entire strength in all three
cases.
Table 2:
The
-dependence of isoscalar EWSR for
Sn.
is
25 fm.
 |
Next: Conclusion
Up: Accuracy of solutions
Previous: The isoscalar 1 mode
Jacek Dobaczewski
2004-07-29