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Constraints for the vector-isovector channel (fourth and sixth orders)
At fourth order we found the following constraints,
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(144) |
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(145) |
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(146) |
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(147) |
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(148) |
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(149) |
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(150) |
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(151) |
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(152) |
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(153) |
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(154) |
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(155) |
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(156) |
and only coupling constant
is unrestricted.
Apart from these 2 free and 23 dependent coupling constants, the
vector-isovector channel of the CE requires that all the remaining
fourth-order coupling constants are forced to be equal to zero. In particular
in the Eq. (156) we showed the vanishing coupling constants, which were found
to be non-vanishing in the scalar-isoscalar channel.
At sixth order we have,
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(157) |
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(158) |
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(159) |
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(160) |
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(161) |
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(162) |
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(163) |
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(164) |
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(165) |
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(166) |
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(167) |
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(168) |
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(169) |
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(170) |
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(171) |
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(172) |
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(173) |
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(174) |
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(175) |
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(176) |
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(177) |
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(178) |
and only coupling constant
is unrestricted.
Apart from 2 free and 39 dependent coupling constants, the
vector-isovector channel of the CE requires that all the remaining
sixth-order coupling constants are forced to be equal to zero. In particular,
in the Eqs. (177)-(178) we showed the vanishing coupling constants that were found
to be non-vanishing in the scalar-isoscalar channel.
The results presented in this section show simultaneously both features we saw
respectively in Appendices A and
B. At all
orders, one can express all coupling constants through only one independent
coupling constant, in such a way that the constraints are
nondiagonal in both spin and isospin space. Again, this fact is due
to the rank of and in the pairs of densities in the final
form of condition (48), which allows the coupling
constants at different spins and isospins to enter into the same
constraints.
Next: Bibliography
Up: Continuity equation and local
Previous: Constraints for the vector-isoscalar
Jacek Dobaczewski
2011-11-11